Hi everyone.
I would like to know if there is a way to export (to excel) the results of the radiation simulation analysis, having it divided in total radiation hitting the surface every hour of the choosen period.
I have this building and I want to understand how exactly the value change in time. It would be amazing to have also the possibility to further divide results pro m2.
Thanks a lot
Iâm still trying to solve the issue. I often get the same error when i try to use the result
Hope it will help to identify the issue
I recommend heeding Asisâs suggestion and also reviewing the forum guidelines, especially the point about only posting the relevant part of your definition.
But I took the part of your file that was about radiation and turned it into a sample of how to do realitme radiation on an hour-by-hour basis:
Thanks, @chris for this example. I think you can add this to the examples folder under ladybug( under installation file)
Hey @Asisnath ,
Iâm purposefully trying to keep the number of official sample files to a minimum right now just because I want to keep the official ones on the github regularly updated over the next few months. After the next stable release, weâll greatly expand the number of official sample files and start converting the hydra samples over to LBT equivalents.
Thanks to both of you @chris @Asisnath and sorry for the messy file
The â2 Real Time Incident Radiationâ component ist interesting, but still doesnât allow me to achieve my goal. I try to clearify it better.
I have ran a simulation for a given period, but the simulation gives me the values measured at each sensor point on the surfaces. That means that the results that I get from the output âresultsâ are not pro m2.
In the immage above you can see that the number of result is different from the m2 of the surfaces (the area of these sub-surface is shown in âcheck2â).
The output description says that the result are in kWh/m2, but as far as I undertand only the preview shows such values.
More than that, in a second moment, I need to collect these vaules pro m2 in each hour of the simulation period.
newLadyBug.gh (409.7 KB)
I have read your question a few times but I donât understand what you are asking. The radiation results output from the component are in kWh/m2. Are you saying that you want to multiply these values by the area of each mesh face to get kWh for each point instead of kWh/m2?
And you can get radiation values for several individual hours at once by grafting the input to the âLB Cumulative Sky Matrixâ component like so:
Just be careful with the number of hours that you run since it can easily be a lot of data that youâre dumping into the Grasshopper UI if you need results separately for each hour
Thanks once again for your time.
The area of the surface is 355 m2. The number of results that I get is 323. This means that the âLB incident radiationâ component divides the surfaces in sub-surfaces with a variable area slightly bigger than 1 meter. So to summarize, 323 sub-surfaces wit an area of 1.05 (more or less).
As far as I understand these 323 values are measured at each sensor at the center of the corresponding sub-surface.
According to that, the 323 values are not kWh/m2 but instead kWh/1.05m2.
I would like to have 355 values, each one representing the kWh/m2. I would also like to have these value as hourly data. It means that I would like to have, for each m2, the kWh at each hour of the day.
If I choose an analysis period going from the 12 December to the 15 December, Iâll like to have 355 valeus * 72 hours = 25 560 values
No, thatâs not correct. The values coming out of the component are in kWh/m2. NOT kWh.
If you want to get the kWh associated with each mesh face or point, you need to multiply the kWh/m2 values coming out of the component by the m2 of each mesh face like so:
Youâll see that the sum of this also aligns with the total radiant energy output from the component:
Hi Chris.
Iâve checked what you sent me.
From this picture I can see that the surface isnât divided in portions of 1m2 each, but in the specific in 323 portions with area equal to:
1.357062
1.357062
1.357111
1.357062
1.357073
1.357062
1.357073
1.357062
1.3571
1.357073
1.357062
1.357073
1.357062
0.630406
1.303698
1.303679
1.303703
1.002939
1.303684
0.630401
âŚ
As I said, if I imput 355 m2 I expect 355 results when the simulation is in kW/m2. Maybe Iâm getting it wrong, Iâm trying to understand.
I think what @chris meant was that for each mesh surface / grid cell, the component gives the radiation value in kWh per m2 of the area of that mesh surface, while the area of each mesh surface may not be exactly 1 m2, even though the grid size is set to 1.
As also shown on the rhino viewport you shared, not all individual mesh surfaces are in exactly the same size. Thus when the component gives an radiation result of 1 kWh/m2, for one mesh surface with an area of 1.10 m2, the total amount of radiation over that mesh surface would be 1.1 kWh. Similarly a mesh surface with an area of 0.90 m2 would have a total radiation of 0.9 kWh. Therefore the total amount of radiation over the entire analysis surface would still add up, and the component does give the radiation values in kWh/m2, while the number of mesh sufaces may not match exactly the number of m2 of the analysis surface, because not every mesh surface is 1m2 exactly.
Thanks @wwkid . Thatâs exactly what I mean.
If youâre looking for an explanation about this, this has to do with Rhinoâs meshing algorithm. You give Rhino an approximate grid size and it tries to keep the dimensions of each mesh face to those dimensions. But it doesnât usually hit this exactly because, otherwise, you wouldnât be able to pass any geometry that you wanted to be meshed. If you pass Rhino a perfect rectangle (without any extra vertices) that can be subdivided by the grid size, only then will you get perfect 1m x 1m grid cells.
